To complete a project, 18 women take 4 more days than the number of days taken by 12 men. If eight men complete the project in 9 days, how… — Answer & Discussion

To complete a project, 18 women take 4 more days than the number of days taken by 12 men. If eight men complete the project in 9 days, how much work will be left when 15 women and 12 men together work for 3 days ?

A$$\frac{2}{3}$$
B$$\frac{3}{4}$$
C$$\frac{3}{2}$$
D$$\frac{1}{4}$$

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Discussion 1

CCommunity23 May 2019

Solution
Using : $\frac{M_1 \times D_1}{W_1} = \frac{M_2 \times D_2}{W_2}$
Acc to ques,
=> $\frac{8 \times 9}{1} = \frac{12 \times D_2}{1}$
=> $D_2 = \frac{72}{12} = 6$
=> Time taken by 18 women = $6 + 4 = 10$ days
=> $(12 \times 6) men \equiv (18 \times 10) women$
= $2 men \equiv 5 women$
We need to find for 15 women and 12 men
= $(6 + 12) = 18 men$
Acc to ques,
=> $\frac{12 \times 6}{1} = \frac{18 \times 3}{W_2}$
=> $W_2 = \frac{54}{72} = \frac{3}{4}$
$\therefore$ Work left = $1 - \frac{3}{4}$
= $\frac{1}{4}$