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If 12 boys or 15 girls can do a work in 48 days, in what time will 24 boys and 6 girls do twice the work?
- A42 days
- B40 days
- C45 days
- D30 days
Answer not set
Discussion 1
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Solution
12 boys or 15 girls can do a work in 48 days
=> $12 boys \equiv 15 girls$
=> $24 boys \equiv 30 girls$
We need to find for 24 boys and 6 girls. Substituting value of 24 boys
=> $24 boys + 6 girls = 36 girls$
Now, using : $\frac{M_1 \times D_1}{W_1} = \frac{M_2 \times D_2}{W_2}$
=> $\frac{15 \times 48}{1} = \frac{36 \times D_2}{2}$
=> $15 \times 48 = 18 \times D_2$
=> $D_2 = \frac{15 \times 48}{18}$
=> $D_2 = 5 \times 8 = 40$ days
12 boys or 15 girls can do a work in 48 days
=> $12 boys \equiv 15 girls$
=> $24 boys \equiv 30 girls$
We need to find for 24 boys and 6 girls. Substituting value of 24 boys
=> $24 boys + 6 girls = 36 girls$
Now, using : $\frac{M_1 \times D_1}{W_1} = \frac{M_2 \times D_2}{W_2}$
=> $\frac{15 \times 48}{1} = \frac{36 \times D_2}{2}$
=> $15 \times 48 = 18 \times D_2$
=> $D_2 = \frac{15 \times 48}{18}$
=> $D_2 = 5 \times 8 = 40$ days