The sum of a series of 5 consecutive odd numbers is 225 The second number of this series is 15 less than the second lowest number of anothe…

Solution
Let the five consecutive odd numbers in increasing order = $(x-4) , (x-2) , (x) , (x+2) , (x+4)$
Sum of these numbers = $(x-4) + (x-2) + (x) + (x+2) + (x+4) = 225$
=> $5x = 225$
=> $x = \frac{225}{5} = 45$
Thus, the odd numbers are = 41 , 43 , 45 , 47 , 49
Let another series of even numbers in increasing order = $(y-4) , (y-2) , (y) , (y+2) , (y+4)$
Also, $43 = (y - 2) - 15$
=> $y = 43 + 15 + 2 = 60$
Thus, highest number of the even series = 60 + 4 = 64
$\therefore$ 60% of 64 = $\frac{60}{100} \times 64 = 38.4$