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The average age of a man and his son is 30 years. The ratio of their ages four years ago was 10 : 3 respectively. What is the difference between the present ages of the man and his son ?
- A28 years
- B16 years
- C26 years
- D44 years
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Solution
Let the age of man be 'x' years.
and the age of son be 'y' years.
According to question,
$\frac{x+y}{2}=30$.
$x+y=60$. eq(1)
and $\frac{x-4}{y-4}=\frac{10}{3}$.
$3x-12=10y-40$.
$10y-3x=28$. eq(2)
Solving eq(1) and eq(2),
y=16,x=44.
Hence, difference between age of man and his son=44-16.
=28.
Let the age of man be 'x' years.
and the age of son be 'y' years.
According to question,
$\frac{x+y}{2}=30$.
$x+y=60$. eq(1)
and $\frac{x-4}{y-4}=\frac{10}{3}$.
$3x-12=10y-40$.
$10y-3x=28$. eq(2)
Solving eq(1) and eq(2),
y=16,x=44.
Hence, difference between age of man and his son=44-16.
=28.