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A bag contains 4 red, 5 yellow and 6 pink balls. Two balls are drawn at random. What is the probability that none of the balls drawn are yellow in colour?
- A$$\frac{1}{7}$$
- B$$\frac{3}{7}$$
- C$$\frac{2}{7}$$
- D$$\frac{5}{14}$$
Answer not set
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0
CCommunity
Solution
Number of non-yellow balls = 4 + 6 = 10
Required Probability = $\frac{^{10}C_2}{^{15}C_2} = \frac{3}{7}$
Number of non-yellow balls = 4 + 6 = 10
Required Probability = $\frac{^{10}C_2}{^{15}C_2} = \frac{3}{7}$
0
CCommunity
Solution
Number of non-yellow balls = 4 + 6 = 10
Required Probability = $\frac{^{10}C_2}{^{15}C_2} = \frac{3}{7}$
Number of non-yellow balls = 4 + 6 = 10
Required Probability = $\frac{^{10}C_2}{^{15}C_2} = \frac{3}{7}$