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The milk and water in two vessels A and B are in the ratio 4 : 3 and 2 : 3 respectively. In what ratio the liquids in both the vessels be m…

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The milk and water in two vessels A and B are in the ratio 4 : 3 and 2 : 3 respectively. In what ratio the liquids in both the vessels be mixed to obtain a new mixture in vessel C consisting half milk and half water?
  • A8 : 3
  • B7 : 5
  • C4 : 3
  • D2 : 3
Answer not set
0
CCommunity
Solution
Let mixture in vessel A = $x$ ml
and mixture in vessel B = $y$ ml
=> Milk in vessel A = $\frac{4x}{7}$
Milk in vessel B = $\frac{2y}{5}$
Acc to ques,
=> $\frac{4x}{7} + \frac{2y}{5} = \frac{1}{2} (x + y)$
=> $\frac{4x}{7} - \frac{x}{2} = \frac{y}{2} - \frac{2y}{5}$
=> $\frac{x}{14} = \frac{y}{10}$
=> $\frac{x}{y} = \frac{14}{10} = \frac{7}{5}$
0
CCommunity
Solution
Let mixture in vessel A = $x$ ml
and mixture in vessel B = $y$ ml
=> Milk in vessel A = $\frac{4x}{7}$
Milk in vessel B = $\frac{2y}{5}$
Acc to ques,
=> $\frac{4x}{7} + \frac{2y}{5} = \frac{1}{2} (x + y)$
=> $\frac{4x}{7} - \frac{x}{2} = \frac{y}{2} - \frac{2y}{5}$
=> $\frac{x}{14} = \frac{y}{10}$
=> $\frac{x}{y} = \frac{14}{10} = \frac{7}{5}$