21
What is the compound interest accrued on an amount of Rs. 12000 at the rate of 9 p.c.p.a. at the end of 2 years.
- ARs. 2545
- BRs. 2257.2
- CRs. 2986
- DRs. 2775.4
Answer not set
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0
CCommunity
Solution
Total amount under compound interest
= $12000 (1 + \frac{9}{100})^2$
= $12000 \times 1.09 \times 1.09$
= $14257.2$
$\therefore$ Compound Interest = 14257.2 - 12000
= Rs. 2,257.2
Total amount under compound interest
= $12000 (1 + \frac{9}{100})^2$
= $12000 \times 1.09 \times 1.09$
= $14257.2$
$\therefore$ Compound Interest = 14257.2 - 12000
= Rs. 2,257.2
0
CCommunity
Solution
Total amount under compound interest
= $12000 (1 + \frac{9}{100})^2$
= $12000 \times 1.09 \times 1.09$
= $14257.2$
$\therefore$ Compound Interest = 14257.2 - 12000
= Rs. 2,257.2
Total amount under compound interest
= $12000 (1 + \frac{9}{100})^2$
= $12000 \times 1.09 \times 1.09$
= $14257.2$
$\therefore$ Compound Interest = 14257.2 - 12000
= Rs. 2,257.2