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If the numerator of a fraction is increased by 125% and the denominator of the fraction is increased by 120%, the resultant fraction is 9/11 . What is the original fraction?
- A3/5
- B4/5
- C4/7
- D7/4
Answer not set
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0
CCommunity
Solution
Let the original fraction = $\frac{x}{y}$
$\therefore \frac{x \times 225}{y \times 220} = \frac{9}{11}$
=> $\frac{x \times 45}{y \times 44} = \frac{9}{11}$
=> $\frac{x}{y} = \frac{9}{11} \times \frac{44}{45}$
=> $\frac{x}{y} = \frac{4}{5}$
Let the original fraction = $\frac{x}{y}$
$\therefore \frac{x \times 225}{y \times 220} = \frac{9}{11}$
=> $\frac{x \times 45}{y \times 44} = \frac{9}{11}$
=> $\frac{x}{y} = \frac{9}{11} \times \frac{44}{45}$
=> $\frac{x}{y} = \frac{4}{5}$
0
CCommunity
Solution
Let the original fraction = $\frac{x}{y}$
$\therefore \frac{x \times 225}{y \times 220} = \frac{9}{11}$
=> $\frac{x \times 45}{y \times 44} = \frac{9}{11}$
=> $\frac{x}{y} = \frac{9}{11} \times \frac{44}{45}$
=> $\frac{x}{y} = \frac{4}{5}$
Let the original fraction = $\frac{x}{y}$
$\therefore \frac{x \times 225}{y \times 220} = \frac{9}{11}$
=> $\frac{x \times 45}{y \times 44} = \frac{9}{11}$
=> $\frac{x}{y} = \frac{9}{11} \times \frac{44}{45}$
=> $\frac{x}{y} = \frac{4}{5}$