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Jar A contains 'X' litre of pure milk only. A 27 litre mixture of milk and water in the respective ratio of 4 : 5, is added to jar A. The new mixture thus formed in jar A contains 70% milk, what is the value of X ?
- A23
- B30
- C27
- D48
Answer not set
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0
CCommunity
Solution
Quantity of milk in 27 litre mixture = $\frac{4}{4 + 5} \times 27 = 12$ litre
Quantity of water = $27 - 12 = 15$ litre
Ratio of milk and water in the new mixture = $70 : 30 = 7 : 3$
Acc to ques,
=> $\frac{X + 12}{15} = \frac{7}{3}$
=> $3X + 36 = 15 \times 7 = 105$
=> $3X = 105 - 36 = 69$
=> $X = \frac{69}{3} = 23$ litre
Quantity of milk in 27 litre mixture = $\frac{4}{4 + 5} \times 27 = 12$ litre
Quantity of water = $27 - 12 = 15$ litre
Ratio of milk and water in the new mixture = $70 : 30 = 7 : 3$
Acc to ques,
=> $\frac{X + 12}{15} = \frac{7}{3}$
=> $3X + 36 = 15 \times 7 = 105$
=> $3X = 105 - 36 = 69$
=> $X = \frac{69}{3} = 23$ litre
0
CCommunity
Solution
Quantity of milk in 27 litre mixture = $\frac{4}{4 + 5} \times 27 = 12$ litre
Quantity of water = $27 - 12 = 15$ litre
Ratio of milk and water in the new mixture = $70 : 30 = 7 : 3$
Acc to ques,
=> $\frac{X + 12}{15} = \frac{7}{3}$
=> $3X + 36 = 15 \times 7 = 105$
=> $3X = 105 - 36 = 69$
=> $X = \frac{69}{3} = 23$ litre
Quantity of milk in 27 litre mixture = $\frac{4}{4 + 5} \times 27 = 12$ litre
Quantity of water = $27 - 12 = 15$ litre
Ratio of milk and water in the new mixture = $70 : 30 = 7 : 3$
Acc to ques,
=> $\frac{X + 12}{15} = \frac{7}{3}$
=> $3X + 36 = 15 \times 7 = 105$
=> $3X = 105 - 36 = 69$
=> $X = \frac{69}{3} = 23$ litre