Joe?s present age is 2/7 th of his father?s present age. Joe?s brother is 3 years older than Joe. The respective ratio between present ages…

Solution
Let joe's father's age be'7x' years.
joe's age=$\frac{2}{7}\times{7x}=2x $years.
joe's brother's age=2x+3 years.
$\frac{joe's father's age}{joe's brother's age}=\frac{14}{5}$.
$\frac{7x}{2x+3}=\frac{14}{5}$.
$x=6$.
Hence, Joe's age=12 years.
Therefore, Option C is correct.

Solution
Let joe's father's age be'7x' years.
joe's age=$\frac{2}{7}\times{7x}=2x $years.
joe's brother's age=2x+3 years.
$\frac{joe's father's age}{joe's brother's age}=\frac{14}{5}$.
$\frac{7x}{2x+3}=\frac{14}{5}$.
$x=6$.
Hence, Joe's age=12 years.
Therefore, Option C is correct.