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The ratio of number of males and number of females in village X is 11:7 respectively. If in village Y, the number of males is 20% more than…

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The ratio of number of males and number of females in village X is 11:7 respectively. If in village Y, the number of males is 20% more than the number of males in village X and the number of females is 12% less than those in village X, then what will be the respective ratio of males to females in village Y ?
  • A15 : 11
  • B17 : 5
  • C17 : 11
  • D23: 9
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0
CCommunity
Solution
Let the number of males in Village X = $11x$
=> Number of females in village X = $7x$
=> Males in village Y = $\frac{120}{100} \times 11x = \frac{66x}{5}$
=> Females in village Y = $\frac{88}{100} \times 7x = \frac{154x}{25}$
$\therefore$ Required ratio
= $(\frac{66x}{5}) : (\frac{154x}{25})$
= $3 : \frac{7}{5}$ = $15 : 7$
0
CCommunity
Solution
Let the number of males in Village X = $11x$
=> Number of females in village X = $7x$
=> Males in village Y = $\frac{120}{100} \times 11x = \frac{66x}{5}$
=> Females in village Y = $\frac{88}{100} \times 7x = \frac{154x}{25}$
$\therefore$ Required ratio
= $(\frac{66x}{5}) : (\frac{154x}{25})$
= $3 : \frac{7}{5}$ = $15 : 7$