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The sum of 68 numbers is 3474. The average of first 22 numbers is 61 and that of last 19 numbers is 44. What will be the average of remaining numbers ?
- A44
- B48
- C46
- D50
Answer not set
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0
CCommunity
Solution
Sum of first 22 numbers = 22 * 61 = 1342
Sum of last 19 numbers = 19 * 44 = 836
Numbers remaining = 68 - 22 - 19 = 27
=> Sum of remaining 19 numbers = 3474 - 1342 - 836 = 1296
$\therefore$ Required average = $\frac{1296}{27}$
= 48
Sum of first 22 numbers = 22 * 61 = 1342
Sum of last 19 numbers = 19 * 44 = 836
Numbers remaining = 68 - 22 - 19 = 27
=> Sum of remaining 19 numbers = 3474 - 1342 - 836 = 1296
$\therefore$ Required average = $\frac{1296}{27}$
= 48
0
CCommunity
Solution
Sum of first 22 numbers = 22 * 61 = 1342
Sum of last 19 numbers = 19 * 44 = 836
Numbers remaining = 68 - 22 - 19 = 27
=> Sum of remaining 19 numbers = 3474 - 1342 - 836 = 1296
$\therefore$ Required average = $\frac{1296}{27}$
= 48
Sum of first 22 numbers = 22 * 61 = 1342
Sum of last 19 numbers = 19 * 44 = 836
Numbers remaining = 68 - 22 - 19 = 27
=> Sum of remaining 19 numbers = 3474 - 1342 - 836 = 1296
$\therefore$ Required average = $\frac{1296}{27}$
= 48