64
40% of 265 + 35% of 180 = 50% of ? + ?% of 80
- A80
- B95.5
- C130
- D125.5
Answer not set
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0
CCommunity
Solution
Let the missing value be y
40% of 265 = 106
35% of 180 = 63
106 + 63 = 169 = 50% of y + y% of 80
= $\frac{y}{2} + \frac{4y}{5}$
$\frac{13y}{10}$ = 169
y = 130
Let the missing value be y
40% of 265 = 106
35% of 180 = 63
106 + 63 = 169 = 50% of y + y% of 80
= $\frac{y}{2} + \frac{4y}{5}$
$\frac{13y}{10}$ = 169
y = 130
0
CCommunity
Solution
Let the missing value be y
40% of 265 = 106
35% of 180 = 63
106 + 63 = 169 = 50% of y + y% of 80
= $\frac{y}{2} + \frac{4y}{5}$
$\frac{13y}{10}$ = 169
y = 130
Let the missing value be y
40% of 265 = 106
35% of 180 = 63
106 + 63 = 169 = 50% of y + y% of 80
= $\frac{y}{2} + \frac{4y}{5}$
$\frac{13y}{10}$ = 169
y = 130