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The number obtained by interchanging the digits of a two-digit number is less than the original number by 63 If the sum of the digits of the number is 11, what is the original number ?
- A29
- B92
- C74
- DCannot be determined
Answer not set
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0
CCommunity
Solution
Let units place digit be x and tens place digit be y.
Original number = 10y + x
Number obtained on interchanging the digits = 10x +y
By given conditond,
x+y = 11
10x +y = 10y +x - 63
9y - 9x = 63
y - x = 7
Solving the linear equations we get,
y=9 and x=2
Original number is 92 i.e option B.
Let units place digit be x and tens place digit be y.
Original number = 10y + x
Number obtained on interchanging the digits = 10x +y
By given conditond,
x+y = 11
10x +y = 10y +x - 63
9y - 9x = 63
y - x = 7
Solving the linear equations we get,
y=9 and x=2
Original number is 92 i.e option B.
0
CCommunity
Solution
Let units place digit be x and tens place digit be y.
Original number = 10y + x
Number obtained on interchanging the digits = 10x +y
By given conditond,
x+y = 11
10x +y = 10y +x - 63
9y - 9x = 63
y - x = 7
Solving the linear equations we get,
y=9 and x=2
Original number is 92 i.e option B.
Let units place digit be x and tens place digit be y.
Original number = 10y + x
Number obtained on interchanging the digits = 10x +y
By given conditond,
x+y = 11
10x +y = 10y +x - 63
9y - 9x = 63
y - x = 7
Solving the linear equations we get,
y=9 and x=2
Original number is 92 i.e option B.