1
A train running at a speed of 60 kmph crosses a platform double its length in 32.4 seconds. What is the length of the platform?
- A108 metres
- B240 meters
- C360 meters
- D90 meters
Answer not set
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0
CCommunity
Solution
Let the length of the train be 'x' metres
Length of the platform = 2x
Distance travelled by the train = x + 2x = 3x
Speed of the train = 60 kmph = $60 \times \frac{5}{18}$ m/sec
Distance = Speed $\times$ Time
$3x = 60 \times \frac{5}{18} \times 32.4$
$x = 180$
The length of the platform = 2x = 360 m
Let the length of the train be 'x' metres
Length of the platform = 2x
Distance travelled by the train = x + 2x = 3x
Speed of the train = 60 kmph = $60 \times \frac{5}{18}$ m/sec
Distance = Speed $\times$ Time
$3x = 60 \times \frac{5}{18} \times 32.4$
$x = 180$
The length of the platform = 2x = 360 m
0
CCommunity
Solution
Let the length of the train be 'x' metres
Length of the platform = 2x
Distance travelled by the train = x + 2x = 3x
Speed of the train = 60 kmph = $60 \times \frac{5}{18}$ m/sec
Distance = Speed $\times$ Time
$3x = 60 \times \frac{5}{18} \times 32.4$
$x = 180$
The length of the platform = 2x = 360 m
Let the length of the train be 'x' metres
Length of the platform = 2x
Distance travelled by the train = x + 2x = 3x
Speed of the train = 60 kmph = $60 \times \frac{5}{18}$ m/sec
Distance = Speed $\times$ Time
$3x = 60 \times \frac{5}{18} \times 32.4$
$x = 180$
The length of the platform = 2x = 360 m