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Two girls and four boys are to be seated in a row, in such a way that the girls do not sit together. In how many different ways can it be done ?
- A720
- B480
- C360
- D240
Answer not set
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0
CCommunity
Solution
In order to solve this question, let us find the total number of ways of arranging four boys and two girls and remove the number of arrangements in which both the girls sit together.
Total number of ways of arranging 4 boys and 2 girls is 6! = 720
Total number of ways of arranging them in such a way that both the girls sit together is (6-1)! * 2 = 240
Hence, the answer is 720 - 240 = 480
In order to solve this question, let us find the total number of ways of arranging four boys and two girls and remove the number of arrangements in which both the girls sit together.
Total number of ways of arranging 4 boys and 2 girls is 6! = 720
Total number of ways of arranging them in such a way that both the girls sit together is (6-1)! * 2 = 240
Hence, the answer is 720 - 240 = 480
0
CCommunity
Solution
In order to solve this question, let us find the total number of ways of arranging four boys and two girls and remove the number of arrangements in which both the girls sit together.
Total number of ways of arranging 4 boys and 2 girls is 6! = 720
Total number of ways of arranging them in such a way that both the girls sit together is (6-1)! * 2 = 240
Hence, the answer is 720 - 240 = 480
In order to solve this question, let us find the total number of ways of arranging four boys and two girls and remove the number of arrangements in which both the girls sit together.
Total number of ways of arranging 4 boys and 2 girls is 6! = 720
Total number of ways of arranging them in such a way that both the girls sit together is (6-1)! * 2 = 240
Hence, the answer is 720 - 240 = 480