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16 times X is equal to 5 times Y. If 8 is subtracted from Y it is 10 more than two times X. What is the sum of X and Y ?
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- C48
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0
CCommunity
Solution
$16X = 5Y$
Also, $Y - 8 = 2X + 10$
=> $Y - 2X = 10 + 8 = 18$
=> $\frac{16X}{5} - 2X = 18$
=> $\frac{16X - 10X}{5} = 18$
=> $6X = 18 \times 5 = 90$
=> $X = \frac{90}{6} = 15$
=> $Y = \frac{16}{5} \times 15$
=> $Y = 16 \times 3 = 48$
$\therefore X + Y = 15 + 48 = 63$
$16X = 5Y$
Also, $Y - 8 = 2X + 10$
=> $Y - 2X = 10 + 8 = 18$
=> $\frac{16X}{5} - 2X = 18$
=> $\frac{16X - 10X}{5} = 18$
=> $6X = 18 \times 5 = 90$
=> $X = \frac{90}{6} = 15$
=> $Y = \frac{16}{5} \times 15$
=> $Y = 16 \times 3 = 48$
$\therefore X + Y = 15 + 48 = 63$
0
CCommunity
Solution
$16X = 5Y$
Also, $Y - 8 = 2X + 10$
=> $Y - 2X = 10 + 8 = 18$
=> $\frac{16X}{5} - 2X = 18$
=> $\frac{16X - 10X}{5} = 18$
=> $6X = 18 \times 5 = 90$
=> $X = \frac{90}{6} = 15$
=> $Y = \frac{16}{5} \times 15$
=> $Y = 16 \times 3 = 48$
$\therefore X + Y = 15 + 48 = 63$
$16X = 5Y$
Also, $Y - 8 = 2X + 10$
=> $Y - 2X = 10 + 8 = 18$
=> $\frac{16X}{5} - 2X = 18$
=> $\frac{16X - 10X}{5} = 18$
=> $6X = 18 \times 5 = 90$
=> $X = \frac{90}{6} = 15$
=> $Y = \frac{16}{5} \times 15$
=> $Y = 16 \times 3 = 48$
$\therefore X + Y = 15 + 48 = 63$