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A project manager hired 16 men to complete a project in 38 days. However, after 30 days, he realized that only 5/9th of the work is complete. How many more men does he need to hire to complete the project on time ?
- A48
- B24
- C32
- D16
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0
CCommunity
Solution
It is clear from the question,
16 men do 5/9th of work in 30 days.
Let 'n' no. of more men are required to complete the remaining work.
Hence, (n+16) men do 4/9th of work in 8 days.
We know that,
$\frac{Amount of work}{No. of men\times{No. of days}}=Constant$.
Hence,
$\frac{5/9}{16\times30}=\frac{4/9}{(n+16)\times8}$.
$n=32$.
Hence, Option C is correct.
It is clear from the question,
16 men do 5/9th of work in 30 days.
Let 'n' no. of more men are required to complete the remaining work.
Hence, (n+16) men do 4/9th of work in 8 days.
We know that,
$\frac{Amount of work}{No. of men\times{No. of days}}=Constant$.
Hence,
$\frac{5/9}{16\times30}=\frac{4/9}{(n+16)\times8}$.
$n=32$.
Hence, Option C is correct.
0
CCommunity
Solution
It is clear from the question,
16 men do 5/9th of work in 30 days.
Let 'n' no. of more men are required to complete the remaining work.
Hence, (n+16) men do 4/9th of work in 8 days.
We know that,
$\frac{Amount of work}{No. of men\times{No. of days}}=Constant$.
Hence,
$\frac{5/9}{16\times30}=\frac{4/9}{(n+16)\times8}$.
$n=32$.
Hence, Option C is correct.
It is clear from the question,
16 men do 5/9th of work in 30 days.
Let 'n' no. of more men are required to complete the remaining work.
Hence, (n+16) men do 4/9th of work in 8 days.
We know that,
$\frac{Amount of work}{No. of men\times{No. of days}}=Constant$.
Hence,
$\frac{5/9}{16\times30}=\frac{4/9}{(n+16)\times8}$.
$n=32$.
Hence, Option C is correct.