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A 275 metre long train crosses a platform of equal length in 33 seconds What is the speed of the train in kmph ?
- A66
- B60
- C64
- D72
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0
CCommunity
Solution
The length of the train is 275 m. Hence, the length of the platform is also 275 m.
The train covers a total distance of 550 m in 33 seconds.
Hence, the speed of the train is $\frac{550}{33} = \frac{50}{3}$ m/s
To convert this speed into kmph, we need to multiply it by $\frac{18}{5}$
Hence, the speed of the train in kmph is $\frac{50}{3}*\frac{18}{5} = 60$ kmph
So, the correct option is option (b)
The length of the train is 275 m. Hence, the length of the platform is also 275 m.
The train covers a total distance of 550 m in 33 seconds.
Hence, the speed of the train is $\frac{550}{33} = \frac{50}{3}$ m/s
To convert this speed into kmph, we need to multiply it by $\frac{18}{5}$
Hence, the speed of the train in kmph is $\frac{50}{3}*\frac{18}{5} = 60$ kmph
So, the correct option is option (b)
0
CCommunity
Solution
The length of the train is 275 m. Hence, the length of the platform is also 275 m.
The train covers a total distance of 550 m in 33 seconds.
Hence, the speed of the train is $\frac{550}{33} = \frac{50}{3}$ m/s
To convert this speed into kmph, we need to multiply it by $\frac{18}{5}$
Hence, the speed of the train in kmph is $\frac{50}{3}*\frac{18}{5} = 60$ kmph
So, the correct option is option (b)
The length of the train is 275 m. Hence, the length of the platform is also 275 m.
The train covers a total distance of 550 m in 33 seconds.
Hence, the speed of the train is $\frac{550}{33} = \frac{50}{3}$ m/s
To convert this speed into kmph, we need to multiply it by $\frac{18}{5}$
Hence, the speed of the train in kmph is $\frac{50}{3}*\frac{18}{5} = 60$ kmph
So, the correct option is option (b)