1
The total price of 6 trousers and 5 shirts is Rs. 2,340. The total price of 7 shirts is Rs. 540 more than the total price of 3 trousers. What is the total price of 4 shirts ?
- ARs.780
- BRs.680
- CRs.760
- DRs.640
Answer not set
Log in or create a free account to reply and vote.
0
CCommunity
Solution
Let price of shirt = Rs. $x$
Price of trouser = Rs. $y$
=> $5x + 6y = 2340$ -----------Eqn(1)
and $7x - 3y = 540$ -----------Eqn(2)
Multiplying eqn(2) by 2 and adding both equations, we get :
=> $19x = 3420$
=> $x = \frac{3420}{19} = 180$
$\therefore$ Cost of 4 shirts = 180 * 4 = Rs. 720
Let price of shirt = Rs. $x$
Price of trouser = Rs. $y$
=> $5x + 6y = 2340$ -----------Eqn(1)
and $7x - 3y = 540$ -----------Eqn(2)
Multiplying eqn(2) by 2 and adding both equations, we get :
=> $19x = 3420$
=> $x = \frac{3420}{19} = 180$
$\therefore$ Cost of 4 shirts = 180 * 4 = Rs. 720
0
CCommunity
Solution
Let price of shirt = Rs. $x$
Price of trouser = Rs. $y$
=> $5x + 6y = 2340$ -----------Eqn(1)
and $7x - 3y = 540$ -----------Eqn(2)
Multiplying eqn(2) by 2 and adding both equations, we get :
=> $19x = 3420$
=> $x = \frac{3420}{19} = 180$
$\therefore$ Cost of 4 shirts = 180 * 4 = Rs. 720
Let price of shirt = Rs. $x$
Price of trouser = Rs. $y$
=> $5x + 6y = 2340$ -----------Eqn(1)
and $7x - 3y = 540$ -----------Eqn(2)
Multiplying eqn(2) by 2 and adding both equations, we get :
=> $19x = 3420$
=> $x = \frac{3420}{19} = 180$
$\therefore$ Cost of 4 shirts = 180 * 4 = Rs. 720