Question discussion

9, 11, 16, 33, 98, ?

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Solution
Number of the form $(2^n + 1)$ are added where n is even number
9 $+ (2^0 + 1)$ = 11
11 $+ (2^2 + 1)$ = 16
16 $+ (2^4 + 1)$ = 33
33 $+ (2^6 + 1)$ = 98
98 $+ (2^8 + 1)$ = 355
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CCommunity
355