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If the product of two successive positive integers is 6162, which is the smaller integer ?
- A78
- B72
- C76
- D74
Answer not set
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0
CCommunity
Solution
Let the two successive positive integers be $(x)$ & $(x + 1)$
Acc to ques,
=> $(x) \times (x + 1) = 6162$
=> $x^2 + x - 6162 = 0$
=> $x = \frac{-1 \pm \sqrt{(1^2) - (4 \times 1 \times -6162)}}{2}$
=> $x = \frac{-1 \pm \sqrt{24649}}{2}$
=> $x = \frac{-1 \pm 157}{2}$
=> $x = 78 , -79$
Since the numbers are positive, => $x = 78$
$\therefore$ Smaller number = 78
Let the two successive positive integers be $(x)$ & $(x + 1)$
Acc to ques,
=> $(x) \times (x + 1) = 6162$
=> $x^2 + x - 6162 = 0$
=> $x = \frac{-1 \pm \sqrt{(1^2) - (4 \times 1 \times -6162)}}{2}$
=> $x = \frac{-1 \pm \sqrt{24649}}{2}$
=> $x = \frac{-1 \pm 157}{2}$
=> $x = 78 , -79$
Since the numbers are positive, => $x = 78$
$\therefore$ Smaller number = 78
0
CCommunity
Solution
Let the two successive positive integers be $(x)$ & $(x + 1)$
Acc to ques,
=> $(x) \times (x + 1) = 6162$
=> $x^2 + x - 6162 = 0$
=> $x = \frac{-1 \pm \sqrt{(1^2) - (4 \times 1 \times -6162)}}{2}$
=> $x = \frac{-1 \pm \sqrt{24649}}{2}$
=> $x = \frac{-1 \pm 157}{2}$
=> $x = 78 , -79$
Since the numbers are positive, => $x = 78$
$\therefore$ Smaller number = 78
Let the two successive positive integers be $(x)$ & $(x + 1)$
Acc to ques,
=> $(x) \times (x + 1) = 6162$
=> $x^2 + x - 6162 = 0$
=> $x = \frac{-1 \pm \sqrt{(1^2) - (4 \times 1 \times -6162)}}{2}$
=> $x = \frac{-1 \pm \sqrt{24649}}{2}$
=> $x = \frac{-1 \pm 157}{2}$
=> $x = 78 , -79$
Since the numbers are positive, => $x = 78$
$\therefore$ Smaller number = 78