In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a… — Answer & Discussion

In each of these question two equations I & II with variables a & b are given You have to solve both the equations to find the values of a & b
Mark answer if

Aa <b
B$$a\leq b$$
Crelationship between a & b cannot be established
Da>b
E$$a\geq b$$

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Discussion 2

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CCommunity08 Apr 2019

Solution
$a^{2}+5a+6=0$

i.e (a+2)(a+3)=0

i.e a=-2, a=-3

.$b^{2}+7b+12=0$

i.e (b+4)(b+3)=0

i.e b=-4, b=-3
Hence, we can deduce that $a \geq b$.

Therefore, option E is correct.

CCommunity30 Apr 2019

Solution
$a^{2}+5a+6=0$

i.e (a+2)(a+3)=0

i.e a=-2, a=-3

.$b^{2}+7b+12=0$

i.e (b+4)(b+3)=0

i.e b=-4, b=-3
Hence, we can deduce that $a \geq b$.

Therefore, option E is correct.