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Five years ago, the ratio between ages of Meena and Sita was 3 : 4. After five years from now the ratio between their ages will be 5 : 6. Find the present age of Meena ?
- A22 years
- B25 years
- C15 years
- D20 years
Answer not set
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0
CCommunity
Solution
Let the ages of Meena and Sita 5 years ago be $3x$ and $4x$ years
=> Present age of Meena = $(3x + 5)$ years
Present age of Sita = $(4x + 5)$ years
Acc. to ques,
=> $\frac{3x + 10}{4x + 10} = \frac{5}{6}$
=> $18x + 60 = 20x + 50$
=> $2x = 60 - 50 = 10$
=> $x = \frac{10}{2} = 5$
$\therefore$ Present age of Meena = $(3 \times 5 + 5) = 20$ years
Let the ages of Meena and Sita 5 years ago be $3x$ and $4x$ years
=> Present age of Meena = $(3x + 5)$ years
Present age of Sita = $(4x + 5)$ years
Acc. to ques,
=> $\frac{3x + 10}{4x + 10} = \frac{5}{6}$
=> $18x + 60 = 20x + 50$
=> $2x = 60 - 50 = 10$
=> $x = \frac{10}{2} = 5$
$\therefore$ Present age of Meena = $(3 \times 5 + 5) = 20$ years
0
CCommunity
Solution
Let the ages of Meena and Sita 5 years ago be $3x$ and $4x$ years
=> Present age of Meena = $(3x + 5)$ years
Present age of Sita = $(4x + 5)$ years
Acc. to ques,
=> $\frac{3x + 10}{4x + 10} = \frac{5}{6}$
=> $18x + 60 = 20x + 50$
=> $2x = 60 - 50 = 10$
=> $x = \frac{10}{2} = 5$
$\therefore$ Present age of Meena = $(3 \times 5 + 5) = 20$ years
Let the ages of Meena and Sita 5 years ago be $3x$ and $4x$ years
=> Present age of Meena = $(3x + 5)$ years
Present age of Sita = $(4x + 5)$ years
Acc. to ques,
=> $\frac{3x + 10}{4x + 10} = \frac{5}{6}$
=> $18x + 60 = 20x + 50$
=> $2x = 60 - 50 = 10$
=> $x = \frac{10}{2} = 5$
$\therefore$ Present age of Meena = $(3 \times 5 + 5) = 20$ years