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The numerator of a fraction is decreased by 25% and the denominator is increased by 250%. If the resultant fraction is 6/5 what is the original fraction ?
- A22/5
- B24/5
- C27/6
- D28/5
Answer not set
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0
CCommunity
Solution
Let the original fraction = $\frac{x}{y}$
Numerator after 25% decrease = $x - \frac{25}{100} x = \frac{75x}{100}$
Denominator after 250% increase = $y + \frac{250}{100} y = \frac{350y}{100}$
Acc to ques,
=> $\frac{\frac{ 75 x }{ 100 }}{\frac{ 350 y }{ 100 }} = \frac{6}{5}$
=> $\frac{3x}{14y} = \frac{6}{5}$
=> $\frac{x}{y} = \frac{6}{5} \times \frac{14}{3}$
=> $\frac{x}{y} = \frac{28}{5}$
Let the original fraction = $\frac{x}{y}$
Numerator after 25% decrease = $x - \frac{25}{100} x = \frac{75x}{100}$
Denominator after 250% increase = $y + \frac{250}{100} y = \frac{350y}{100}$
Acc to ques,
=> $\frac{\frac{ 75 x }{ 100 }}{\frac{ 350 y }{ 100 }} = \frac{6}{5}$
=> $\frac{3x}{14y} = \frac{6}{5}$
=> $\frac{x}{y} = \frac{6}{5} \times \frac{14}{3}$
=> $\frac{x}{y} = \frac{28}{5}$
0
CCommunity
Solution
Let the original fraction = $\frac{x}{y}$
Numerator after 25% decrease = $x - \frac{25}{100} x = \frac{75x}{100}$
Denominator after 250% increase = $y + \frac{250}{100} y = \frac{350y}{100}$
Acc to ques,
=> $\frac{\frac{ 75 x }{ 100 }}{\frac{ 350 y }{ 100 }} = \frac{6}{5}$
=> $\frac{3x}{14y} = \frac{6}{5}$
=> $\frac{x}{y} = \frac{6}{5} \times \frac{14}{3}$
=> $\frac{x}{y} = \frac{28}{5}$
Let the original fraction = $\frac{x}{y}$
Numerator after 25% decrease = $x - \frac{25}{100} x = \frac{75x}{100}$
Denominator after 250% increase = $y + \frac{250}{100} y = \frac{350y}{100}$
Acc to ques,
=> $\frac{\frac{ 75 x }{ 100 }}{\frac{ 350 y }{ 100 }} = \frac{6}{5}$
=> $\frac{3x}{14y} = \frac{6}{5}$
=> $\frac{x}{y} = \frac{6}{5} \times \frac{14}{3}$
=> $\frac{x}{y} = \frac{28}{5}$