0
The compound interest on a certain sum for 2 years at 20% per annum is Rs.880/?. The simple interest on the same sum for double the time at half the rate percent per annum is :
- A800/
- B1,000/
- C1,200/
- D1,600/
Answer not set
Log in or create a free account to reply and vote.
0
CCommunity
Solution
Let the sum = Rs. $P$
$C.I. = P [(1 + \frac{R}{100})^T - 1]$
=> $880 = P [(1 + \frac{20}{100})^2 - 1]$
=> $880 = P (\frac{36}{25} - 1)$
=> $880 = \frac{11P}{25}$
=> $P = \frac{880 \times 25}{11} = 2000$
Now, S.I. on Rs. 2,000 for 4 years at 10%
= $\frac{2000 \times 10 \times 4}{100}$
= $20 \times 40 = 800$
Let the sum = Rs. $P$
$C.I. = P [(1 + \frac{R}{100})^T - 1]$
=> $880 = P [(1 + \frac{20}{100})^2 - 1]$
=> $880 = P (\frac{36}{25} - 1)$
=> $880 = \frac{11P}{25}$
=> $P = \frac{880 \times 25}{11} = 2000$
Now, S.I. on Rs. 2,000 for 4 years at 10%
= $\frac{2000 \times 10 \times 4}{100}$
= $20 \times 40 = 800$
0
CCommunity
Solution
Let the sum = Rs. $P$
$C.I. = P [(1 + \frac{R}{100})^T - 1]$
=> $880 = P [(1 + \frac{20}{100})^2 - 1]$
=> $880 = P (\frac{36}{25} - 1)$
=> $880 = \frac{11P}{25}$
=> $P = \frac{880 \times 25}{11} = 2000$
Now, S.I. on Rs. 2,000 for 4 years at 10%
= $\frac{2000 \times 10 \times 4}{100}$
= $20 \times 40 = 800$
Let the sum = Rs. $P$
$C.I. = P [(1 + \frac{R}{100})^T - 1]$
=> $880 = P [(1 + \frac{20}{100})^2 - 1]$
=> $880 = P (\frac{36}{25} - 1)$
=> $880 = \frac{11P}{25}$
=> $P = \frac{880 \times 25}{11} = 2000$
Now, S.I. on Rs. 2,000 for 4 years at 10%
= $\frac{2000 \times 10 \times 4}{100}$
= $20 \times 40 = 800$