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If the perimeter of a rectangle is 138 metres and the difference between the length and breadth is 7 metres, what is the area of the rectangle ?
- A1216 square metres
- B1147 square metres
- C1184 square metres
- D1178 square metres
Answer not set
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0
CCommunity
Solution
Let the length be x and breadth be y.
x - y = 7
The perimeter of rectangle is 138
2x + 2y = 138
x + y = 69
2x = 76
x = 38
y = 31
Area of rectangle = 31*38 = 1178
Option D is correct.
Let the length be x and breadth be y.
x - y = 7
The perimeter of rectangle is 138
2x + 2y = 138
x + y = 69
2x = 76
x = 38
y = 31
Area of rectangle = 31*38 = 1178
Option D is correct.
0
CCommunity
Solution
Let the length be x and breadth be y.
x - y = 7
The perimeter of rectangle is 138
2x + 2y = 138
x + y = 69
2x = 76
x = 38
y = 31
Area of rectangle = 31*38 = 1178
Option D is correct.
Let the length be x and breadth be y.
x - y = 7
The perimeter of rectangle is 138
2x + 2y = 138
x + y = 69
2x = 76
x = 38
y = 31
Area of rectangle = 31*38 = 1178
Option D is correct.
0
CCommunity
1178