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A boatman rows downstream a distance of 30 km in 6 hours and up stream a distance of 24 km in 6 hours. The ratio of speed of boat in still water and speed of current is
- A9 : 1
- B8 : 1
- C9 : 2
- D8 : 3
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0
CCommunity
Solution
Let speed of boat in still water = $x$ km/h
and speed of current = $y$ km/h
Now, $\frac{30}{x + y} = 6$
=> $x + y = 5$
and $\frac{24}{x - y} = 6$
=> $x - y = 4$
Solving above equations, we get :
$x = \frac{9}{2}$ and $y = \frac{1}{2}$
=> $x : y = 9 : 1$
Let speed of boat in still water = $x$ km/h
and speed of current = $y$ km/h
Now, $\frac{30}{x + y} = 6$
=> $x + y = 5$
and $\frac{24}{x - y} = 6$
=> $x - y = 4$
Solving above equations, we get :
$x = \frac{9}{2}$ and $y = \frac{1}{2}$
=> $x : y = 9 : 1$
0
CCommunity
Solution
Let speed of boat in still water = $x$ km/h
and speed of current = $y$ km/h
Now, $\frac{30}{x + y} = 6$
=> $x + y = 5$
and $\frac{24}{x - y} = 6$
=> $x - y = 4$
Solving above equations, we get :
$x = \frac{9}{2}$ and $y = \frac{1}{2}$
=> $x : y = 9 : 1$
Let speed of boat in still water = $x$ km/h
and speed of current = $y$ km/h
Now, $\frac{30}{x + y} = 6$
=> $x + y = 5$
and $\frac{24}{x - y} = 6$
=> $x - y = 4$
Solving above equations, we get :
$x = \frac{9}{2}$ and $y = \frac{1}{2}$
=> $x : y = 9 : 1$