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A,B C D and E are five consecutive odd numbers. Average of A and C is 59. What is the smallest number ?
- A65
- B63
- C61
- D57
Answer not set
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0
CCommunity
Solution
Let the five numbers be a, a+2, a+4, a+6 and a+8.
The average of A and C is 59.
Therefore, a + a+4 = 2*59
Or 2a + 4 = 118
Therefore, a = 57
Hence, the smallest number is 57.
Let the five numbers be a, a+2, a+4, a+6 and a+8.
The average of A and C is 59.
Therefore, a + a+4 = 2*59
Or 2a + 4 = 118
Therefore, a = 57
Hence, the smallest number is 57.
0
CCommunity
Solution
Let the five numbers be a, a+2, a+4, a+6 and a+8.
The average of A and C is 59.
Therefore, a + a+4 = 2*59
Or 2a + 4 = 118
Therefore, a = 57
Hence, the smallest number is 57.
Let the five numbers be a, a+2, a+4, a+6 and a+8.
The average of A and C is 59.
Therefore, a + a+4 = 2*59
Or 2a + 4 = 118
Therefore, a = 57
Hence, the smallest number is 57.
0
CCommunity
A ,A+2, A+4 ,A+6, A+8
A+C/2=59
So smaller number is 57
A+C/2=59
So smaller number is 57