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The average monthly income of A and B is Rs. 7,760. The average monthly income of B and C is Rs. 10,990 and that of C and A is Rs. 9,070. What is the annual income of B ?
- ARs. 1,20,240
- BRs. 1,24,480
- CRs..1,12,360
- DRs. 1,28,120
Answer not set
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0
CCommunity
Solution
Monthly income of :
$(A + B) = 2 \times 7,760$ = Rs. $15,520$
$(B + C) = 2 \times 10,990$ = Rs. $21,980$
$(C + A) = 2 \times 9,070$ = Rs. $18,140$
Adding above equations, we get :
=> $2 (A + B + C)$ = $15,520 + 21,980 + 18,140$ = $55,640$
=> $A + B + C = \frac{55,640}{2} = 27,820$
From equation (3) above
=> $B = 27,820 - 18,140 = 9,680$
$\therefore$ B's annual salary = $12 \times 9680$
= Rs. $1,16,160$
Monthly income of :
$(A + B) = 2 \times 7,760$ = Rs. $15,520$
$(B + C) = 2 \times 10,990$ = Rs. $21,980$
$(C + A) = 2 \times 9,070$ = Rs. $18,140$
Adding above equations, we get :
=> $2 (A + B + C)$ = $15,520 + 21,980 + 18,140$ = $55,640$
=> $A + B + C = \frac{55,640}{2} = 27,820$
From equation (3) above
=> $B = 27,820 - 18,140 = 9,680$
$\therefore$ B's annual salary = $12 \times 9680$
= Rs. $1,16,160$
0
CCommunity
Solution
Monthly income of :
$(A + B) = 2 \times 7,760$ = Rs. $15,520$
$(B + C) = 2 \times 10,990$ = Rs. $21,980$
$(C + A) = 2 \times 9,070$ = Rs. $18,140$
Adding above equations, we get :
=> $2 (A + B + C)$ = $15,520 + 21,980 + 18,140$ = $55,640$
=> $A + B + C = \frac{55,640}{2} = 27,820$
From equation (3) above
=> $B = 27,820 - 18,140 = 9,680$
$\therefore$ B's annual salary = $12 \times 9680$
= Rs. $1,16,160$
Monthly income of :
$(A + B) = 2 \times 7,760$ = Rs. $15,520$
$(B + C) = 2 \times 10,990$ = Rs. $21,980$
$(C + A) = 2 \times 9,070$ = Rs. $18,140$
Adding above equations, we get :
=> $2 (A + B + C)$ = $15,520 + 21,980 + 18,140$ = $55,640$
=> $A + B + C = \frac{55,640}{2} = 27,820$
From equation (3) above
=> $B = 27,820 - 18,140 = 9,680$
$\therefore$ B's annual salary = $12 \times 9680$
= Rs. $1,16,160$