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Three years ago, Manini's age at that time was thrice of Rinu's age at that time. The respective ratio between Rinu's age six years hence a…

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Three years ago, Manini's age at that time was thrice of Rinu's age at that time. The respective ratio between Rinu's age six years hence and Manini's age eight years hence, will be 3 : 7. What will be Rinu's age two years hence ? (in years)
  • A20
  • B26
  • C29
  • D32
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0
CCommunity
Solution
Let the present ages of Manini be M and Rinu be R respectively

3 years ago the age of Manini was M-3 and Rinu's age was R-3
It is given that M-3 = 3(R-3)
Now after 8 years age of Manini = M+8 and Rinu's age after 6 years will be = R + 6
$\frac{R+6}{M+8} = \frac{3}{7}$
Solving the above equations , R = 18 years
2 years hence Rinu's age will be 18 + 2 = 20 years
0
CCommunity
Solution
Let the present ages of Manini be M and Rinu be R respectively

3 years ago the age of Manini was M-3 and Rinu's age was R-3
It is given that M-3 = 3(R-3)
Now after 8 years age of Manini = M+8 and Rinu's age after 6 years will be = R + 6
$\frac{R+6}{M+8} = \frac{3}{7}$
Solving the above equations , R = 18 years
2 years hence Rinu's age will be 18 + 2 = 20 years