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A is four times efficient as B. B started the work and after 6 days, A joined him. If the whole work was completed in 12 days, in how many days A alone can finish the whole piece of work ?
- A10
- B9
- C8
- D12
Answer not set
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0
CCommunity
Solution
Let work = 1 units
Let time taken by A to complete the work = $x$ days
=> Time taken by B = $4x$ days
Acc to ques,
=> $\frac{12}{4x} + \frac{6}{x} = 1$
=> $\frac{6}{x} (\frac{1}{2} + 1) = 1$
=> $\frac{3}{2} = \frac{x}{6}$
=> $x = \frac{3}{2} \times 6$
=> $x = 9$ days
Let work = 1 units
Let time taken by A to complete the work = $x$ days
=> Time taken by B = $4x$ days
Acc to ques,
=> $\frac{12}{4x} + \frac{6}{x} = 1$
=> $\frac{6}{x} (\frac{1}{2} + 1) = 1$
=> $\frac{3}{2} = \frac{x}{6}$
=> $x = \frac{3}{2} \times 6$
=> $x = 9$ days
0
CCommunity
Solution
Let work = 1 units
Let time taken by A to complete the work = $x$ days
=> Time taken by B = $4x$ days
Acc to ques,
=> $\frac{12}{4x} + \frac{6}{x} = 1$
=> $\frac{6}{x} (\frac{1}{2} + 1) = 1$
=> $\frac{3}{2} = \frac{x}{6}$
=> $x = \frac{3}{2} \times 6$
=> $x = 9$ days
Let work = 1 units
Let time taken by A to complete the work = $x$ days
=> Time taken by B = $4x$ days
Acc to ques,
=> $\frac{12}{4x} + \frac{6}{x} = 1$
=> $\frac{6}{x} (\frac{1}{2} + 1) = 1$
=> $\frac{3}{2} = \frac{x}{6}$
=> $x = \frac{3}{2} \times 6$
=> $x = 9$ days