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The difference between 67% of a number and 43% of the same number is 912. What is 19% of that number ?
- A608
- B798
- C722
- D684
Answer not set
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0
CCommunity
Solution
Let the number be $100x$
Acc to ques,
=> $(67 - 43) \%$ of $100x = 912$
=> $\frac{24}{100} \times 100x = 912$
=> $x = \frac{912}{24} = 38$
=> Number = 100 * 38 = 3800
$\therefore$ 19% of 3800 = $\frac{19}{100} * 3800$
= 722
Let the number be $100x$
Acc to ques,
=> $(67 - 43) \%$ of $100x = 912$
=> $\frac{24}{100} \times 100x = 912$
=> $x = \frac{912}{24} = 38$
=> Number = 100 * 38 = 3800
$\therefore$ 19% of 3800 = $\frac{19}{100} * 3800$
= 722
0
CCommunity
Solution
Let the number be $100x$
Acc to ques,
=> $(67 - 43) \%$ of $100x = 912$
=> $\frac{24}{100} \times 100x = 912$
=> $x = \frac{912}{24} = 38$
=> Number = 100 * 38 = 3800
$\therefore$ 19% of 3800 = $\frac{19}{100} * 3800$
= 722
Let the number be $100x$
Acc to ques,
=> $(67 - 43) \%$ of $100x = 912$
=> $\frac{24}{100} \times 100x = 912$
=> $x = \frac{912}{24} = 38$
=> Number = 100 * 38 = 3800
$\therefore$ 19% of 3800 = $\frac{19}{100} * 3800$
= 722