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A is 2 years older than B while B is 3 years younger than C. The ratio of age of A, 6 years hence and B, 2 years ago is 5:3. What was age of C, 6 years ago ?
- A12 years
- B19 years
- C15 years
- D14 years
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0
CCommunity
Solution
let the present age of C be y years
So age of B will be y-3 years
And present age of A will be y-1 years
6 years hence age of A will be y+5 and age of B 2 years was y-5
It is given that $\frac{y+5}{y-5}$=$\frac{5}{3}$
y = 20 years
Hence age of C before 6 years = 20 -6 =14 years
let the present age of C be y years
So age of B will be y-3 years
And present age of A will be y-1 years
6 years hence age of A will be y+5 and age of B 2 years was y-5
It is given that $\frac{y+5}{y-5}$=$\frac{5}{3}$
y = 20 years
Hence age of C before 6 years = 20 -6 =14 years
0
CCommunity
Solution
let the present age of C be y years
So age of B will be y-3 years
And present age of A will be y-1 years
6 years hence age of A will be y+5 and age of B 2 years was y-5
It is given that $\frac{y+5}{y-5}$=$\frac{5}{3}$
y = 20 years
Hence age of C before 6 years = 20 -6 =14 years
let the present age of C be y years
So age of B will be y-3 years
And present age of A will be y-1 years
6 years hence age of A will be y+5 and age of B 2 years was y-5
It is given that $\frac{y+5}{y-5}$=$\frac{5}{3}$
y = 20 years
Hence age of C before 6 years = 20 -6 =14 years