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If the area of the rectangle is 1248 square metres and its breadth is 32 metres, what is its perimeter ?
- A142 metres
- B128 metres
- C148 metres
- D124 metres
Answer not set
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CCommunity
Solution
As we know that the area of a rectangle is $ l \times b $ (Where l is length of rectangle and b is breadth of rectangle)
Which is 1248 square meter with breadth(b) 32 meters
So length will be = $\frac{1248}{32} = 39$
Hence, parameter will be equal to = 2(39+32) = 142 m
As we know that the area of a rectangle is $ l \times b $ (Where l is length of rectangle and b is breadth of rectangle)
Which is 1248 square meter with breadth(b) 32 meters
So length will be = $\frac{1248}{32} = 39$
Hence, parameter will be equal to = 2(39+32) = 142 m
0
CCommunity
Solution
As we know that the area of a rectangle is $ l \times b $ (Where l is length of rectangle and b is breadth of rectangle)
Which is 1248 square meter with breadth(b) 32 meters
So length will be = $\frac{1248}{32} = 39$
Hence, parameter will be equal to = 2(39+32) = 142 m
As we know that the area of a rectangle is $ l \times b $ (Where l is length of rectangle and b is breadth of rectangle)
Which is 1248 square meter with breadth(b) 32 meters
So length will be = $\frac{1248}{32} = 39$
Hence, parameter will be equal to = 2(39+32) = 142 m