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A link has a bandwidth of 1 Mbps and a one-way propagation delay of 20 ms. A stop-and-wait protocol sends 1,000-byte frames and the acknowl…

1315Medium DSSSB TGT Computer Science 0 replies

A link has a bandwidth of 1 Mbps and a one-way propagation delay of 20 ms. A stop-and-wait protocol sends 1,000-byte frames and the acknowledgement transmission time is negligible. The link utilisation is

A1/12
B2/7
C1/6
D1/3

Correct answer: C

Explanation

The frame transmission time is 8000 bits ÷ 1 Mbps = 8 ms and the round trip is 40 ms, so utilisation = 8/(8 + 40) = 1/6 (about 16.7%).

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