Question discussion

A woman works continuously for 7 days in the kitchen and refuses to work on the 8th day when her husband takes over. If she starts her work…

134063Medium 2 replies 851 views
0
A woman works continuously for 7 days in the kitchen and refuses to work on the 8th day when her husband takes over. If she starts her work on a Sunday, the 11th time she rests will be on which day of the week?
  • AWednesday
  • BTuesday
  • CMonday
  • DFriday
Answer not set
0
CCommunity
Total days = Working days + rest days

Given: rest days = 11

? Working days = (rest days) × 7

∴ Total days = 11 × 7 + 11 = 88

? 1st day = Sunday so we have to find the day on 88th day:

So, 88/7 remainder = 4

Now we just have to find the day on 4th day i.e. Sun + Mon + Tue + Wed

So When She will take rest 11th time, the day is Wednesday.
0
CCommunity
Total days = Working days + rest days

Given: rest days = 11

? Working days = (rest days) × 7

∴ Total days = 11 × 7 + 11 = 88

? 1st day = Sunday so we have to find the day on 88th day:

So, 88/7 remainder = 4

Now we just have to find the day on 4th day i.e. Sun + Mon + Tue + Wed

So When She will take rest 11th time, the day is Wednesday.