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The average of three numbers is 58. The first number is 3/4 of the third number. If the third number is 24 more than the second number, then what will be the difference between the first number and the second number?
- A24
- B6
- C16
- D18
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0
CCommunity
The average of three numbers = 58
So, the sum of three numbers = 58 × 3 = 174
Let third number be 4x
So, the first number = 3x
So, the second number = 4x - 24
According to the question
⇒ 3x + 4x - 24 + 4x = 174
⇒ 11x = 198
⇒ x = 18
So, the first number = 3 × 18 = 54
The second number = 4 × 18 - 24 = 48
∴ The difference between the first number and the second number = 54 - 48 = 6
So, the sum of three numbers = 58 × 3 = 174
Let third number be 4x
So, the first number = 3x
So, the second number = 4x - 24
According to the question
⇒ 3x + 4x - 24 + 4x = 174
⇒ 11x = 198
⇒ x = 18
So, the first number = 3 × 18 = 54
The second number = 4 × 18 - 24 = 48
∴ The difference between the first number and the second number = 54 - 48 = 6
0
CCommunity
The average of three numbers = 58
So, the sum of three numbers = 58 × 3 = 174
Let third number be 4x
So, the first number = 3x
So, the second number = 4x - 24
According to the question
⇒ 3x + 4x - 24 + 4x = 174
⇒ 11x = 198
⇒ x = 18
So, the first number = 3 × 18 = 54
The second number = 4 × 18 - 24 = 48
∴ The difference between the first number and the second number = 54 - 48 = 6
So, the sum of three numbers = 58 × 3 = 174
Let third number be 4x
So, the first number = 3x
So, the second number = 4x - 24
According to the question
⇒ 3x + 4x - 24 + 4x = 174
⇒ 11x = 198
⇒ x = 18
So, the first number = 3 × 18 = 54
The second number = 4 × 18 - 24 = 48
∴ The difference between the first number and the second number = 54 - 48 = 6