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Work done by (x + 4) men in (x + 5) days is equal to the work done by (x – 5) men in (x + 20) days. Then the value of x is
- A25
- B30
- C15
- D20
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0
CCommunity
Given, work done by (x + 4) men in (x + 5) days is equal to the work done by (x – 5) men in (x + 20) days.
∴ Total work = (x + 4)(x + 5) = (x – 5)(x + 20)
⇒ x2 + 9x + 20 = x2 + 15x -100
⇒ 6x = 120
⇒ x = 20
∴ Total work = (x + 4)(x + 5) = (x – 5)(x + 20)
⇒ x2 + 9x + 20 = x2 + 15x -100
⇒ 6x = 120
⇒ x = 20
0
CCommunity
Given, work done by (x + 4) men in (x + 5) days is equal to the work done by (x – 5) men in (x + 20) days.
∴ Total work = (x + 4)(x + 5) = (x – 5)(x + 20)
⇒ x2 + 9x + 20 = x2 + 15x -100
⇒ 6x = 120
⇒ x = 20
∴ Total work = (x + 4)(x + 5) = (x – 5)(x + 20)
⇒ x2 + 9x + 20 = x2 + 15x -100
⇒ 6x = 120
⇒ x = 20