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A box consist of 5 rupees, 2 rupees and 1 rupee coins and their value are in the ratio of 15 : 4 : 2 respectively. If there are total 112 coins, then how many 2 rupees coins are there in the box?
- A32
- B48
- C64
- D24
Answer not set
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0
CCommunity
Given that,
Total coins = 112
Let Rs. 15x be value of 5 rupees coins, Rs. 4x be the value of 2 rupees coins and 2x be the value of 1 rupee coins
According to the question,
15x/5 + 4x/2 + 2x/1 = 112
⇒ 3x + 2x + 2x = 112
⇒ 7x = 112
⇒ x = 16
∴ 2 rupees coins are there in the box = 4x/2 = 2x = 2 × 16 = 32
Total coins = 112
Let Rs. 15x be value of 5 rupees coins, Rs. 4x be the value of 2 rupees coins and 2x be the value of 1 rupee coins
According to the question,
15x/5 + 4x/2 + 2x/1 = 112
⇒ 3x + 2x + 2x = 112
⇒ 7x = 112
⇒ x = 16
∴ 2 rupees coins are there in the box = 4x/2 = 2x = 2 × 16 = 32
0
CCommunity
Given that,
Total coins = 112
Let Rs. 15x be value of 5 rupees coins, Rs. 4x be the value of 2 rupees coins and 2x be the value of 1 rupee coins
According to the question,
15x/5 + 4x/2 + 2x/1 = 112
⇒ 3x + 2x + 2x = 112
⇒ 7x = 112
⇒ x = 16
∴ 2 rupees coins are there in the box = 4x/2 = 2x = 2 × 16 = 32
Total coins = 112
Let Rs. 15x be value of 5 rupees coins, Rs. 4x be the value of 2 rupees coins and 2x be the value of 1 rupee coins
According to the question,
15x/5 + 4x/2 + 2x/1 = 112
⇒ 3x + 2x + 2x = 112
⇒ 7x = 112
⇒ x = 16
∴ 2 rupees coins are there in the box = 4x/2 = 2x = 2 × 16 = 32