33
The population of a town is 200000. It increases annually at the rate of 10%. What will be the population after 2 years?
- A240000
- B242000
- C221000
- D244000
Answer not set
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0
CCommunity
Population of a town is 2,00,000
∴ Population will be after 2 years $(= 2,00,000 \times {\left( {1 + \frac{{10}}{{110}}} \right)^2} = 2,00,000 \times \frac{{110}}{{100}} \times \frac{{110}}{{100}} = 2,42,000)$
∴ Population will be after 2 years $(= 2,00,000 \times {\left( {1 + \frac{{10}}{{110}}} \right)^2} = 2,00,000 \times \frac{{110}}{{100}} \times \frac{{110}}{{100}} = 2,42,000)$
0
CCommunity
Population of a town is 2,00,000
∴ Population will be after 2 years $(= 2,00,000 \times {\left( {1 + \frac{{10}}{{110}}} \right)^2} = 2,00,000 \times \frac{{110}}{{100}} \times \frac{{110}}{{100}} = 2,42,000)$
∴ Population will be after 2 years $(= 2,00,000 \times {\left( {1 + \frac{{10}}{{110}}} \right)^2} = 2,00,000 \times \frac{{110}}{{100}} \times \frac{{110}}{{100}} = 2,42,000)$