The solution of the recurrence T(n) = 2T(n/2) + n log n isAΘ(n)BΘ(n log² n)CΘ(n log n)DΘ(n²) Correct answer: B ExplanationHere f(n) = n log n = Θ(n^(log₂2) · log n), the extended case 2 of the Master theorem with k = 1, giving Θ(n log^(k+1) n) = Θ(n log² n). Join the discussion Report an error