Question discussion

α and β are the roots of the quadratic equation x2 - x - 1 = 0. What is the value of α8 + β8?

137198Medium 2 replies 673 views
0
CCommunity
Product of roots, α × β = -1

Sum of roots, α + β = -b/a

⇒ α + β = 1 (? b = -1 and a = 1)

Squaring on both the sides,

⇒ (α + β)2 = 12

⇒ α2 + β2 + 2αβ = 1

⇒ α2 + β2 + 2(-1) = 1

⇒ α2 + β2 = 3

Again squaring on both the sides,

⇒ (α2 + β2)2 = 32

⇒ α4 + β4 + 2α2β2 = 9

⇒ α4 + β4 = 7

Again squaring on both the sides,

⇒ (α4 + β4)2 = 72

⇒ α8 + β8 + 2α4β4 = 49

∴ α8 + β8 = 47
0
CCommunity
Product of roots, α × β = -1

Sum of roots, α + β = -b/a

⇒ α + β = 1 (? b = -1 and a = 1)

Squaring on both the sides,

⇒ (α + β)2 = 12

⇒ α2 + β2 + 2αβ = 1

⇒ α2 + β2 + 2(-1) = 1

⇒ α2 + β2 = 3

Again squaring on both the sides,

⇒ (α2 + β2)2 = 32

⇒ α4 + β4 + 2α2β2 = 9

⇒ α4 + β4 = 7

Again squaring on both the sides,

⇒ (α4 + β4)2 = 72

⇒ α8 + β8 + 2α4β4 = 49

∴ α8 + β8 = 47