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What is the sum of the first 12 terms of an arithmetic progression if the first term is 3 and last term is 47?
- A260
- B300
- C280
- D220
Answer not set
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0
CCommunity
The sum of ‘n’ terms of an A.P. is given as,
Sum = (n/2) × (first term + last term)
Given, n = 12
First term = 3
Last term = 47
∴ Sum of 12 terms of A.P. = (12/2) × (3 + 47) = 6 × 50 = 300
Sum = (n/2) × (first term + last term)
Given, n = 12
First term = 3
Last term = 47
∴ Sum of 12 terms of A.P. = (12/2) × (3 + 47) = 6 × 50 = 300
0
CCommunity
300 is the correct answer.