0In an RSA system with p = 3, q = 11 and public exponent e = 7, the ciphertext for the plaintext 2 isA17B29C23D31 Correct answer: B Explanationn = 3 × 11 = 33, so C = 2⁷ mod 33 = 128 mod 33 = 29. Join the discussion Report an error Share