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How many distinct states does a 4-bit Johnson (twisted-ring) counter have in its normal counting sequence?

1536Medium DSSSB TGT Computer Science 0 replies 1 views
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How many distinct states does a 4-bit Johnson (twisted-ring) counter have in its normal counting sequence?

  • A4
  • B8
  • C15
  • D16
Correct answer: B

Explanation

A Johnson counter with n flip-flops cycles through 2n states, so a 4-bit Johnson counter has 8 states (a plain 4-bit binary counter has 16).

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