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If A = cosx cosy, B = sinx siny and C = sin2x + sin2y then the value of A2 - B2
- AC
- B1 - C
- C1 + C
- DC - 1
Answer not set
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0
CCommunity
A = cosx cos y, B = sinx sin y, C = sin2x sin2y
A2 - B2 = (cosx cos y)2 - (sinx sin y)2
= (1-sin2x) (1-sin2y) - sin2x sin2y
= 1 - sin2y - sin2x + sin2x sin2y - sin2x sin2y
= 1 - (sin2y + sin2x)
= 1 - (sin2x + sin2y)
A2 - B2 = 1 - C
A2 - B2 = (cosx cos y)2 - (sinx sin y)2
= (1-sin2x) (1-sin2y) - sin2x sin2y
= 1 - sin2y - sin2x + sin2x sin2y - sin2x sin2y
= 1 - (sin2y + sin2x)
= 1 - (sin2x + sin2y)
A2 - B2 = 1 - C
0
CCommunity
Answer is (1-C)