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What is the output of the following Python code?def make(): n = 0 def inc(): nonlocal n n += 1 return n return inc a = make(); b = make() p…

What is the output of the following Python code?

def make():
    n = 0
    def inc():
        nonlocal n
        n += 1
        return n
    return inc
a = make(); b = make()
print(a(), a(), b())

Correct answer: D

Explanation

Each call to make() creates its own enclosing variable n, so a counts 1, 2 while b starts afresh at 1.

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