Question discussion

The depth of tension cracks in a soft clay (ϕu = 0) is

158760Medium 2 replies 812 views
32
The depth of tension cracks in a soft clay (ϕu = 0) is
  • A\(\frac{{4{c_u}}}{\gamma}\)
  • B\(\frac{{2{C_u}}}{\gamma}\)
  • C\(\frac{{{C_u}}}{\gamma}\)
  • D\(\frac{{{C_u}}}{{2\gamma}}\)
Answer not set
0
CCommunity
$({p_a} = {k_a}\gamma Z - 2{c_u}\sqrt {{k_a}} )$

Let Zc = Depth of tension crack

At Z = Zc, pa = 0

$(\therefore 0 = {k_a}\gamma {Z_c} - 2{c_u}\sqrt {{k_a}} )$

$(\therefore {Z_c} = \frac{{2{c_u}}}{{\gamma \sqrt {{k_a}} }})$

For ?u = 0, ka = 1

∴ Depth of tension crack

$({Z_c} = \frac{{2{c_u}}}{\gamma })$
0
CCommunity
As per the condition of soft clay the answer is

Option B