32
If O = 16, FOR = 42, then what is FRONT equal to?
- A61
- B65
- C73
- D78
Answer not set
Log in or create a free account to reply and vote.
0
CCommunity
Alphabet
A
B
C
D
E
F
G
H
I
J
K
L
M
Value
1
2
3
4
5
6
7
8
9
10
11
12
13
Alphabet
N
O
P
Q
R
S
T
U
V
W
X
Y
Z
Value
14
15
16
17
18
19
20
21
22
23
24
25
26
Arranging the letters in alphabetical order and adding 1 in their values we get value of
O = 15 + 1 = 16
Similarly FOR = (6 + 1) + (15 + 1) + (18 + 1) = 42
Hence FRONT = (6 + 1) + (18 + 1) + (15 + 1) + (14 + 1) + (20 + 1)
= 7 + 19 + 16 + 15 + 21 = 78.
A
B
C
D
E
F
G
H
I
J
K
L
M
Value
1
2
3
4
5
6
7
8
9
10
11
12
13
Alphabet
N
O
P
Q
R
S
T
U
V
W
X
Y
Z
Value
14
15
16
17
18
19
20
21
22
23
24
25
26
Arranging the letters in alphabetical order and adding 1 in their values we get value of
O = 15 + 1 = 16
Similarly FOR = (6 + 1) + (15 + 1) + (18 + 1) = 42
Hence FRONT = (6 + 1) + (18 + 1) + (15 + 1) + (14 + 1) + (20 + 1)
= 7 + 19 + 16 + 15 + 21 = 78.
0
CCommunity
o value is 15
o=16 i.e. 15+1=16
for=(6+1)+(15+1)+(18+1)
=42
front=(6+1)+(8+1)+(15+1)+(14+1)+(20+1)
=78
o=16 i.e. 15+1=16
for=(6+1)+(15+1)+(18+1)
=42
front=(6+1)+(8+1)+(15+1)+(14+1)+(20+1)
=78